You are here

Power Pack - Chain Reaction Part 2

Section:

Switch to alternative gallery
Average: 4.7 (1989 votes)

Add new comment

1 + 8 =
Solve this simple math problem and enter the result. E.g. for 1+3, enter 4.
Tonantzintla 618's picture
Joined: 05/08/2024

So... Moral of the story is: Don't teach your superpowered younger sister to blow and fuck you or she'll explode. Aight

Anonymous (not verified)
Anonymous's picture

Lord save us all from the dip pit of greed and lust the night is long and cold, help us god not to cave to the warmth of the Satanic embrace, my lord, bless us with your way and forgive out eternal ignorance.

Anonymous (not verified)
Anonymous's picture

Guys help me learn logarithms . Will pay u absolutely nothing

Anonymous (not verified)
Anonymous's picture

aight so you logarithms are the opposite of exponentiating. So if you do 3^10 then log base 3 of that will be 10. It undoesz the 3^.

if you wanna learn the basics probably look up eddie woo or some math mf on yt

Anonymous (not verified)
Anonymous's picture

yes, in other terms:

log_a(b) = the number of times you have to moltiplicate a to get b:

(e.g):

log_2(8) = 3

because 2^3=2×2×2=8

so we had to moltiplicate 2 for 3 times to get 8!

hope this is easy to understand!

Anonymous (not verified)
Anonymous's picture

Further more, now we can represent the exponential and logarithmic forms as b^x = m ---> log_b m = x, where (b) represents the base number, (x) is a variable, and (m) is the result. Since any number (where b ≠ 0) (b)^0 = 1, there exists log_b 1 = 0. Also any number (b)^1 = b ---> log_b b = 1.

Anonymous (not verified)
Anonymous's picture

You will find through a time consuming and lengthy process, the exponential constant, I wish to not write it all down right now, but just know that 2^x = m --> log_2 m = x and 3^x = m ---> log_3 m = x and there exist a constant (e) that sits between 2 and 3 (≈ 2.71...), found by a growth calculation (1 + 1/n)^n. This will help later on with cancelations and such for calculations, (Like how you can cross cancel rational number in multiplication). Now there exists e^x and ln x. Where ln x is also just log_e e = x.

Anonymous (not verified)
Anonymous's picture

Correction : ln(x) <---> log_e(x)

Anonymous (not verified)
Anonymous's picture

So now, whenever you are asked to solve for x, just know that ln(e^x) = x and e^lnx = x. 
 

I'm sure this can be explained better, and I humbly request further support in assisting this person in their journey through logarithms. 
 

But hopefully you get the gist.

TheHentai_R8r's picture
Joined: 13/11/2023

(8/10) Incog do be cogging

Anonymous (not verified)
Anonymous's picture

Can't wait to see the new pages tonight

Anonymous (not verified)
Anonymous's picture

Me dik cum

Anonymous (not verified)
Anonymous's picture

May Doc have mercy on your soul 

Anonymous (not verified)
Anonymous's picture

You cannot be talking like that when you clicked on this website. 

Anonymous (not verified)
Anonymous's picture

Well fall is almost here so this will soon be back up and running, and then we wait again for sultry summer.

Anonymous (not verified)
Anonymous's picture

this real early sex education and hands on experence too

Anonymous (not verified)
Anonymous's picture

Part 3

Anonymous (not verified)
Anonymous's picture

Lol may the Lord forgive us is a tag

Anonymous (not verified)
Anonymous's picture

Now to continue with the original 

Anonymous (not verified)
Anonymous's picture

The author is putting this on hold for now as this page ends an arc, and he is switching and updating Sultry Summer once he finishes an arc for that, he will come back here

Don't expect this to be updated for a good while

Anonymous (not verified)
Anonymous's picture

fuck

Anonymous (not verified)
Anonymous's picture

So... p3?

Drip Man's picture
Joined: 16/04/2021

Can't she move faster than sound? she could have easily made it outside in that timeframe

Anonymous (not verified)
Anonymous's picture

is this even legal

Niko OneShot's picture
Joined: 13/07/2022

Probably. Idk

Anonymous (not verified)
Anonymous's picture

Are you legally allowed to be here?

Anonymous (not verified)
Anonymous's picture

Are you legally allowed to be here?

SexuallyAttached2You's picture
Joined: 11/09/2022

don't be such a stupid human being and go search the results for yourself

SexuallyAttached2You's picture
Joined: 11/09/2022

A random administrator picked this pfp for me. I didn't expect something so honorable...

SexuallyAttached2You's picture
Joined: 11/09/2022

IM KEEPING THIS BITCH. YOU CANT DO ANYTHING TO STOP ME

Pages